Ok, fair enough.

What does it mean to circle a tree? To you, that is.

It's all good. I understand what you are saying about the skwerl. I just have a different perspective.

this

I get so excited when you get all QA on me. ;)

And always keeps the tree between himself and the hunter

This is the crucial bit of information.

Consider a bicycle wheel for example. The hole in the rim for the valve stem is opposite the seam of the rim. The wheel revolves around the axle. The valve stem and seam each go around the axle every revolution. They do not go around each other. They do go around the position the other previously occupied however. Compare this to a ratchet wrench. The socket is the axis, the handle goes around the axis, but the handle does not go around itself.
The squirrel always keeps the tree between himself and the hunter. The tree is the axis, the squirrel is the seam on the rim and the hunter is the valve stem.

No, the hunter does not walk around his gun. His gun is not stationary, it moves with him. He may walk around the location his gun used to be, but that is not the same as walking around his gun. Unless he has one of those special mag-lev guns that just hangs in mid air while you circumambulate around it. Otherwise, if it is a normal gun then he will be taking it with him when he walks around the tree.

FFS here's the next one: (I have updated it so you modern "new math" educated folks can understand it.


Setting aside their differences, Classicman and Infinite Monkey pool their money and invest in some very tiny houses on very tiny lots in a very sketchy neighborhood.
Classic invests $5000. and Infi invests $3000 and they buy three identical houses. Classic and Infi each choose a home for them own selfs. They then sell the remaining house to some complete rube for $8000. How should they divvy the cash?

Classic owns 5/8ths of the company stock, Infi owns 3/8ths. So the dividends go 5/8ths to Classic ($5,000) and 3/8ths to Infi ($3,000.)

It should also be noted that when they sell Infi's house, she will owe 5/8ths of those proceeds to Classic as well.

Is the understanding that they are each to own their own house after the transaction? If so, they should divide the money as clod says then infi should give classic $2,000 so he will end up with $7,000 and a house and she will end up with $1000 and a house (he owns 5/8 of her shouse, she owns 3/8 of his, assume all three houses worth 8,000 at that time, so the difference is 2/8)

But that was too easy so it must be wrong.

You forgot to factor in the divorce attorneys cut. They both get zilch.

I get all the money - That way I 'll have a down payment on a new Maxima.

You are wrong; your answer was right.
You are wrong about being wrong so your answer is correct.

And now for something completely different:

1.111111111111 bushels

total minus 10 percent equals 90 percent.

90 percent (what the miller gave the customer) equals one bushel.

.9*total = 1 bushel

(.9*total)/.9 = (1 bushel)/.9

total == 1.11111111111 bushels

Oh no, I think we've established that when you are giving part of something to someone, the answer is to borrow some extra so you don't have to work in decimals.

LULZ!

please state your answer as a fraction in order to claim your point for the winning answer.

Wise ass.
When you are dividing an entire living creature that may be the case as a fractional piece of livestock is a) of limited value and b) more than likely no longer living and therefore no longer livestock.

Bushels of grain can be divided fractionally so there is no need to borrow anything. However it is a pain in the ass to measure out 1/9 of a bushel.

1/9 of 8 gallons is .888888888888889 gallons...

No, the grain comes to the mill in a different form. We have to know the reduction in volume that occurs during the milling.

Very sneaky Bruce.

Happy Mental Nut Year!

Think carefully on this one.

$110

Unknown ...Which transaction? Or all three combined?
Since we don't know what he paid originally (before he sold for $90)
then we can only assume

* horsume

It doesn't make any sense, so I'll say $190. That's probably this book's answer.:p:

Depends how much he bought the whore for in the first place

"The hunter walked around the tree"
Was he on horseback? Did he get the horse from this guy?

Of course (a horse a horse) we could wonder about any original price, but I don't think you're supposed to add elements to a story problem. Maybe he got a horse for his birthday...this book isn't the SATs. There's an answer.

Any simple math I do agrees with BigV...110, but then we get into the "too easy" category.

$20. Had $90 at first, $110 last.

He would have $110 if he also still had the horse.

See, I only learned opposite math! :blush:

I'm dumb.

But what did he pay for it initially?

And I'm still not done with that circular squirrel yet....

Heh heh heh

I think he woke up one morning and it was in his barn.

Yeah, yeah, tell it to the Judge.:rolleyes:

:)

The horse or the squirrel?

This was a good idea for a thread.

The next several nuts are just math tricks or as the Brits like to say maths trick,

whatever. I am putting all of them up along with the advertisements and then the nut nut proper. One has to remember things were different in 1921. No calculators for instance.

The tree is only the existential quantifier of your circular squirrel.
Take it out of the equation and the logic is obvious. ;)

I thought so as well, but I thought the answer was no he does not.
Hence the repeated question.

Yes. The hunter does not go around the squirrel. They both go around the tree but the squirrel always keeps the tree between himself and the hunter. For the hunter to go around the squirrel it would need to stay in one place on the tree.

Why? If the squirrel is ALWAYS on the tree and the hunter circles the tree ...
This must be a matter of semantics or definitions.

Well you know what else? Heisenberg says both are orbiting the tree, and you can't say for certain where either one is in their orbital path at a given time. But you do know that the hunter is in a higher orbital than the squirrel, and the higher orbital plane does encircle the lower orbital plane. The more time that passes, the higher the statistical probability that the hunter has orbited the squirrel. Nyeah.

NO, you have to re-read the question. There is no treadmill involved. They are moving at the same rate around the same axis. The squirrel will never be encircled by the hunter. The spot where the squirrel had been will be encircled, but not the squirrel itself.

And another thing, you all avoided
How I need a drink, alcoholic in nature, after the tough chapters involving quantum mechanics!

Cipher - I like that. Isn't that what Jethro Bodine used to say?

Yes, but did he affix them? Another cromulent word that is under-used these days.

and can you affix nothing to something?

The answer to #33 is yes.

The force on the pulley will be the same with two equal weights (W+W) or with a weight (W) on one side and the second side anchored to the floor.

No, it's geometry.

I assume you mean squirlomatree.

Yes. And it's really non-debateable. ;)

If the hunter circles the tree and the squirrel is ON the tree, then the hunter circles the squirrel.

If he got the horse for free....

selling for 90, he has 90....
buying it for 80, leaves him 10 from his 90
selling for 100 .... he has 110.

what am i missing?

I think this must be a linguistic thing, "how much did he make on the transaction?" I think is meant to mean how much more did he make on the second transaction.

Just be glad this isn't 1921

The earth does not orbit mercury

Maybe this experiment will help: you will need someone to play the squirrel and you will need a piece of rope.

Premise: If you go around someone or something with a piece of rope (with one end of the rope affixed to the someone or something, the other end in your hand) then when you have made a complete circle they will have one turn of rope wrapped around them. Do you agree?

If you do not encircle them then there will be no rope wrapped around them. Do you agree?

Now, try going around your pretend squirrel with one end of the rope in your hand and the other affixed to the squirrel. If the squirrel is stationary you will encircle the squirrel with the rope.
Now try the same thing only this time, the squirrel always turns in the same direction as you. For added realism you can do this outside around a tree. See how many times you managed to encircle the squirrel with the rope.

Have someone record a video of it and put it up on youtube.

No, she means squirrelonatree

but it does circle it

Which is a branch of geonatree.

And what about #33?

Foot, would you be willing to scan the Book's answers too?

What, and ruin all the fun?

Oh all right. There aren't many explanations however.

How about the moon, does the earth circle that?

(She moves in circles, and those circles move.)

I know what you mean, can you believe it? Or are you referring to your answer to #33? Or would you like another Rolling Rock?
so, No. Yes. Yes.

here's 1-21