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Old 09-23-2006, 10:28 PM   #1
glatt
 
Join Date: Jul 2003
Location: Arlington, VA
Posts: 27,717
Quote:
Originally Posted by tw
(a+b)(a-b) = b (a-b)
a+b = b
To get from (a+b)(a-b) = b (a-b)
to
a+b = b
you must divide each side by (a-b). That's great, except...

since a=b, then (a-b) = (a-a) = 0

Only Chuck Norris can divide by zero.
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Old 09-24-2006, 05:58 PM   #2
tw
Read? I only know how to write.
 
Join Date: Jan 2001
Posts: 11,933
Quote:
Originally Posted by glatt
since a=b, then (a-b) = (a-a) = 0
It is called the trivial solution.
a * c = b * c
has a unique solution (for real numbers) EXCEPT when c = 0. We tend to forget the other part of that algebraic relationship: that c cannot equal 0. Once c becomes zero, then any number can equal any other.

Naive will then proclaim that math can be manipulated - another interpretation of "lie, damn lies, and statistics". Instead, by providing only a half fact (by forgetting the part where c cannot equal zero), then a mistake occurs.

c=0 is called the trivial solution; an overlooked mathematical error that glatt has successfully identifed.
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Old 09-25-2006, 11:30 AM   #3
glatt
 
Join Date: Jul 2003
Location: Arlington, VA
Posts: 27,717
Quote:
Originally Posted by tw
an overlooked mathematical error that glatt has successfully identifed.
To be fair, Happy Monkey beat me to it. I just didn't see his solution because he hid it behind a white font color. It wasn't until Beestie quoted him later that I saw his entire post.
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